Additional Criteria • Total heat release (MJ/m²) • pHRR (kW/m²) • Time of Ignition (s) • Smoke production • Acidity • Flaming droplets This example demonstrates the need to consider the complete cable design, as using XLPE for the insulation layer would not give the required Euroclass.

Industrial Valle del Cinca S/N Apartado Barbastro, Huesca E-22300 Spain Activity: Design and Manufacture of Specialty Engineered Thermoplastics Activity: Design and Manufacture of Specialty Engineered Thermoplastics Facility: Avient Corporation - Oricain (Pamplona), Spain Pol.

The following chart compares cumulative TSR on our common shares against the cumulative total return of the S&P 500 Index and the S&P Mid Cap Chemicals Index for the five-year period December 31, 2010 to December 31, 2015, assuming in each case a fixed investment of $100 and reinvestment of all dividends. Our performance has exceeded the S&P 500 Index as well as the S&P Mid Cap Chemicals Index. The $1 million deduction limit generally does not apply to compensation that satisfies Section 162(m)’s requirements for qualified performance-based compensation.

CHAPTER 3 | PART DESIGN GUIDELINES Wall Thickness (mm) C o o li n g T im e ( S e c ) 40 35 30 25 20 15 10 5 0 0 1 2 3 4 ABS PC Nylon 6/6 Figure 2 - Designing for Wall Thickness Changes Bad Better Recommended Recommended Poor High Stress Ideal Figure 3 - Internal and External Radius Guidelines .5W Min Inside Rad + W Poor High Volume FIGURE 1 - Wall thickness vs . cooling time of various plastics FIGURE 2 - Designing for wall thickness changes FIGURE 3 - Internal and external radius guidelines Design Guide 9 RIB DESIGN GUIDELINES The minimum distance ribs should be spaced is three times the nominal wall thickness (3W) . This will FIGURE 43 - Non-Newtonian Fluid Flow Low Level of Orientation Frozen Layer Highly Oriented Laminates Gate Pressure Transducer A Pressure Transducer B Hydraulic x 10 Filling Hold Start of mold shrinkage Time Pack P re s s u re A B FIGURE 45 - Non-Newtonian fluid flow Relative Viscosity = Transfer Position * Fill Time Shear Rate = 1 Fill time FIGURE 46 - Pressure vs . End of Fill Part Length Dynamic Pressure Hydrostatic Pressure P re s s u re Gate End Part FIGURE 61 - Deflection Equations H F WLMax Deflection: 0.002" (0.05mm) 1 = W • H3 12 _______ bending = F • L3 48 • E • I _______ 4 π tc = h2 1n π2 • a • Tmelt – Tcoolant Teject – Tcoolant tc = D2 1.61n 23.1 • a Tmelt – Tcoolant Teject – Tcoolant a = k p * Cp Qmoldings = mmoldings • Cp • Tme • Cplt – Teject cooling nlines moldings tccooling Vcoolant line nmax, coolant • Pcoolant • Cp, coolant Dmax = 4 • Pcoolant • Vcoolant π • µcoolant • 4000 Dmin = Pcoolant • Lline • V2coolant5 10π • ∆Pline 4 π tc = h2 1n π2 • a • Tmelt – Tcoolant Teject – Tcoolant tc = D2 1.61n 23.1 • a Tmelt – Tcoolant Teject – Tcoolant a = k p * Cp Qmoldings = mmoldings • Cp • Tme • Cplt – Teject cooling nlines moldings tccooling Vcoolant line nmax, coolant • Pcoolant • Cp, coolant Dmax = 4 • Pcoolant • Vcoolant π • µcoolant • 4000 Dmin = Pcoolant • Lline • V2coolant5 10π • ∆Pline 4 π tc = h2 1n π2 • a • Tmelt – Tcoolant Teject – Tcoolant tc = D2 1.61n 23.1 • a Tmelt – Tcoolant Teject – Tcoolant a = k p * Cp Qmoldings = mmoldings • Cp • Tme • Cplt – Teject cooling nlines moldings tccooling Vcoolant line nmax, coolant • Pcoolant • Cp, coolant Dmax = 4 • Pcoolant • Vcoolant π • µcoolant • 4000 Dmin = Pcoolant • Lline • V2coolant5 10π • ∆Pline FIGURE 60 - Pressure vs Part Length FIGURE 61 - Deflection equations FIGURE 62 - For Plate Shaped Parts FIGURE 63 - For Cylindrical Shaped Parts Design Guide 49 • M Moldings = Combined mass of molded parts • C p = Specific Heat of the material Step 3 – Heat Removal Rate • N lines = The total number of independent cooling lines there are in the mold • t c = The cooling time required by the part (Determined in step 1) Step 4 – Coolant Volumetric Flow Rate • ΔT Max,Coolant = Change in coolant Temperature During Molding (1°C) • ρ Coolant = Density of coolant • CP = Specific heat of coolant Step 5 – Determine Cooling Line Diameter • ρ Coolant = Density of coolant • V Coolant = Volumetric flow rate of coolant • μ Coolant = Viscosity of coolant • ΔP line = Max pressure drop per line (Usually equals half of the pump capacity) • L Line = Length of the cooling lines COOLING LINE SPACING 4 π tc = h2 1n π2 • a • Tmelt – Tcoolant Teject – Tcoolant tc = D2 1.61n 23.1 • a Tmelt – Tcoolant Teject – Tcoolant a = k p * Cp Qmoldings = mmoldings • Cp • Tme • Cplt – Teject cooling nlines moldings tccooling Vcoolant line nmax, coolant • Pcoolant • Cp, coolant Dmax = 4 • Pcoolant • Vcoolant π • µcoolant • 4000 Dmin = Pcoolant • Lline • V2coolant5 10π • ∆Pline 4 π tc = h2 1n π2 • a • Tmelt – Tcoolant Teject – Tcoolant tc = D2 1.61n 23.1 • a Tmelt – Tcoolant Teject – Tcoolant a = k p * Cp Qmoldings = mmoldings • Cp • Tme • Cplt – Teject cooling nlines moldings tccooling Vcoolant line nmax, coolant • Pcoolant • Cp, coolant Dmax = 4 • Pcoolant • Vcoolant π • µcoolant • 4000 Dmin = Pcoolant • Lline • V2coolant5 10π • ∆Pline 4 π tc = h2 1n π2 • a • Tmelt – Tcoolant Teject – Tcoolant tc = D2 1.61n 23.1 • a Tmelt – Tcoolant Teject – Tcoolant a = k p * Cp Qmoldings = mmoldings • Cp • Tme • Cplt – Teject cooling nlines moldings tccooling Vcoolant line nmax, coolant • Pcoolant • Cp, coolant Dmax = 4 • Pcoolant • Vcoolant π • µcoolant • 4000 Dmin = Pcoolant • Lline • V2coolant5 10π • ∆Pline 4 π tc = h2 1n π2 • a • Tmelt – Tcoolant Teject – Tcoolant tc = D2 1.61n 23.1 • a Tmelt – Tcoolant Teject – Tcoolant a = k p * Cp Qmoldings = mmoldings • Cp • Tme • Cplt – Teject cooling nlines moldings tccooling Vcoolant line nmax, coolant • Pcoolant • Cp, coolant Dmax = 4 • Pcoolant • Vcoolant π • µcoolant • 4000 Dmin = Pcoolant • Lline • V2coolant5 10π • ∆Pline 4 π tc = h2 1n π2 • a • Tmelt – Tcoolant Teject – Tcoolant tc = D2 1.61n 23.1 • a Tmelt – Tcoolant Teject – Tcoolant a = k p * Cp Qmoldings = mmoldings • Cp • Tme • Cplt – Teject cooling nlines moldings tccooling Vcoolant line nmax, coolant • Pcoolant • Cp, coolant Dmax = 4 • Pcoolant • Vcoolant π • µcoolant • 4000 Dmin = Pcoolant • Lline • V2coolant5 10π • ∆Pline 4 π tc = h2 1n π2 • a • Tmelt – Tcoolant Teject – Tcoolant tc = D2 1.61n 23.1 • a Tmelt – Tcoolant Teject – Tcoolant a = k p * Cp Qmoldings = mmoldings • Cp • Tme • Cplt – Teject cooling nlines moldings tccooling Vcoolant line nmax, coolant • Pcoolant • Cp, coolant Dmax = 4 • Pcoolant • Vcoolant π • µcoolant • 4000 Dmin = Pcoolant • Lline • V2coolant5 10π • ∆Pline 2D < H line < 5D H line < W line < 2H line FIGURE 70 - Cooling Line Spacing FIGURE 64 - Heat Transfer Equation FIGURE 65 - Total Cooling for Mold FIGURE 66 - Cooling Required by Each Line FIGURE 68 - Max Diameter Equation FIGURE 69 - Min Diameter Equation FIGURE 67 - Volumetric Flow Rate Equation 50 Gravi-Tech ADHESIVE ADVANTAGES DISADVANTAGES Cyanoacrylate Rapid, one-part process Various viscosities Can be paired with primers for polyolefins Poor strength Low stress crack resistance Low chemical resistance Epoxy High strength Compatible with various substrates Tough Requires mixing Long cure time Limited pot life Exothermic Hot Melt Solvent-free High adhesion Different chemistries for different substrates High temp dispensing Poor high temp performance Poor metal adhesion Light Curing Acrylic Quick curing One component Good environmental resistance Oxygen sensitive Light source required Limited curing configurations Polyurethane High cohesive strength Impact and abrasion resistance Poor high heat performance Requires mixing Silicone Room temp curing Good adhesion Flexible Performs well in high temps Low cohesive strength Limited curing depth Solvent sensitive No-Mix Acrylic Good peel strength Fast cure Adhesion to variety of substrates Strong odor Exothermic Limited cure depth Design Guide 51 Bibliography 1 .

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